Learn about the reactions between cations and various reagents.
Result: Formation of a black precipitate of lead sulfide (PbS).
Explanation: Lead ions react with hydrogen sulfide to form insoluble lead sulfide.
Result: Formation of a blue precipitate of copper hydroxide (Cu(OH)₂).
Explanation: Sodium hydroxide reacts with copper ions to form copper hydroxide.
Result: Formation of a brown-black precipitate of bismuth sulfide (Bi₂S₃).
Explanation: Bismuth ions react with hydrogen sulfide to form bismuth sulfide.
Result: Formation of a brown precipitate of iron(III) hydroxide (Fe(OH)₃).
Explanation: Sodium hydroxide reacts with iron ions to form iron hydroxide.
Result: Initially forms a grey-green precipitate of chromium hydroxide (Cr(OH)₃), which can dissolve in excess NaOH to form a chromate complex.
Explanation: Chromium ions react with sodium hydroxide, but excess NaOH may cause further reaction.
Result: Formation of a white precipitate of aluminum hydroxide (Al(OH)₃), which dissolves in excess NaOH.
Explanation: Aluminum reacts to form the hydroxide, which is amphoteric, meaning it can dissolve in excess NaOH.
Result: Formation of a white precipitate of zinc hydroxide (Zn(OH)₂), which dissolves in excess NaOH.
Explanation: Similar to aluminum, zinc hydroxide dissolves in excess NaOH to form a soluble zincate ion.
Result: Formation of a yellow precipitate of barium chromate (BaCrO₄).
Explanation: Barium reacts with chromate ions to form an insoluble yellow precipitate of barium chromate.
Result: The solution turns brown as iodine is liberated, and iron(II) forms.
Explanation: Iron(III) ions are reduced by iodide to form iron(II) and iodine.
Result: Formation of a deep blue solution due to the formation of tetraamminecopper(II) complex.
Explanation: Ammonium hydroxide reacts with copper to form a soluble complex.
Temperature: 25 °C
Result will be shown here